How do I calculate the power radiated by a PointDipole source?

Date	Category
2023-12-08 11:40:56	Sources

The tidy3d.PointDipole source is normalized such that the power injected in a homogeneous material of refractive index \(n\) at frequency \(\omega = 2\pi f\) is given by

\(\frac{\omega^2}{12\pi}\frac{\mu_0 n}{c}\).​​​​​

To calculate the radiated power of a dipole in the presence of dispersive, lossy, or non-homogeneous materials, you can use a tidy3d.FluxMonitor box. Refer to this notebook for an example.